No, when you cancel it out you're left with: (1+1) = 1 You don't work out each of the sums and then divide it etc. you just cancel it down...

If you work it out like you think you should, without cancelling, there's a problem with the maths of it. (1+1)(1-1)/(1-1) 1(1-1)/(1-1) If you type in eather of those on a calculator it comes up saying 'Maths Error' or something along the lines of that so you can't work it out that way...

I'm talking about when you finally get (1+1)=1. Why can't you add those 2 ones [(1+1)]? And btw, I never use my calculator for math. I don't trust the things.

Eh? That doesn't make sense to me. When I do an equation, even if it ends up being something = something. I still have to break it down. I.E. adding the two ones.

It's one of those questions where if you do something to one side you have to do it to the other side... So you can't add because there is nothing to add on the right-hand side...

hey wait a min i have problem with this part X=Y . why x=y? if somebody tell me why x=y then im agree with whole of that .

Because if X=1 and Y=1 then X=Y because X and Y are the same number... @Lorn: There are such things as them... I'll try and get an example for my maths book [EDIT:] Okay, I found one 4x - 5 = 25 Then you add a 5 to each side to even out the -5 on the left-hand side. You get: 4x = 30 Then you divide each side by 4 so you are left with x on one side... x = 7.5 For the (1+1)=1 question, you have what x and y are so you don't need to find out what x is, but you still use the same method

Because if X=1 and Y=1 then X=Y because X and Y are the same number... [/b][/quote] But how does one plus one equal one? I don't get that. :\

Because if X=1 and Y=1 then X=Y because X and Y are the same number... @Lorn: There are such things as them... I'll try and get an example for my maths book [EDIT:] Okay, I found one 4x - 5 = 25 Then you add a 5 to each side to even out the -5 on the left-hand side. You get: 4x = 30 Then you divide each side by 4 so you are left with x on one side... x = 7.5 For the (1+1)=1 question, you have what x and y are so you don't need to find out what x is, but you still use the same method [/b][/quote] It's the way the sum is set out... It doesn't use normal this add this equal this, you have to cancel things from each side... (1+1)(1-1)/(1-1) = 1(1-1)/(1-1) You have to do the same thing to each side of the equation so you times by (1-1) which leaves you with... (1+1)(1-1) = 1(1-1) Then, you have to get rid of the 2 things that are the same... ie. the (1-1)'s... You are then left with: (1+1) = 1 You can't do a lot more than that because you don't have anything else to cancel out... The most you can do is get rid of the brackets... You have to times out the brackets by the number in front of them. Because there is no number, you have to times them out by 1, you are left with: 1+1 = 1

Still don't get it. I mean, I get what you're talking about in that problem in the math book. That one makes sense to me. But I can't make sense out of (1+1)=1. I never seen a answer like that.

If you work out them answer then that's what it is... It's probably because you're not used to such an unordinary answer to a question

Happens is. The way I learned math is like this. Yes, it's possible to get something like that as an answer. [(1+1)=1] But when getting something like that. You put NS for "No Solution". Since it's impossible for 2 to equal 1.

But it is, because it's there... It's probably just the way that you work it out... [/b][/quote] But 2 isn't 1. 1 is 1. It isn't the way I work it out. It's the final answer that matters. And you say its (1+1)=1. I find that to be a no solution. Because it's like saying 9=10, which is not true. Therefore, no solution. I never came accross a answer that had something like 2=1 and not put no solution as the true answer. Ya get me?